Extraction of Periodic signal masked by noise using correlation.
Aim: To extract a periodic signal masked by noise using correlation.
EQUIPMENTS:
PC with windows (95/98/XP/NT/2000).
MATLAB Software.
Program Code:
clear all;
close all;
clc;
n=256;
k1=0:n-1;
x=cos(32*pi*k1/n)+sin(48*pi*k1/n);
plot(k1,x)
%Module to find period of input signl
k=2;
xm=zeros(k,1);
ym=zeros(k,1);
hold on
for i=1:k
[xm(i) ym(i)]=ginput(1);
plot(xm(i), ym(i),'r*');
end
period=abs(xm(2)-xm(1));
rounded_p=round(period);
m=rounded_p
% Adding noise and plotting noisy signal
y=x+randn(1,n);
figure
plot(k1,y)
% To generate impulse train with the period as that of input signal
d=zeros(1,n);
for i=1:n
if (rem(i-1,m)==0)
d(i)=1;
end
end
%Correlating noisy signal and impulse train
cir=cxcorr1(y,d);
%plotting the original and reconstructed signal
m1=0:n/4;
figure
plot(m1,x(m1+1),'r',m1,m*cir(m1+1));
Output:
Result: In this experiment the Extraction of periodic signal masked by noise using correlation have been verified using MATLAB.
Viva Questions:
1. Define the condition for distortion less transmission through the system.
Ans: Transmission is said to be distortion less if the input and output have identical wave shapes within a multiplicative constant.A delayed output that retains the input waveform is also considered distortion less.Thus in distortion-less transmission, the input x(t) and output y(t) satisfy the condition:
y(t) = Kx(t - t) where t is the delay time and k is a constant
2. What is filter?
Ans: Electronic filters are electronic circuits which perform signal processing functions, specifically to remove unwanted frequency components from the signal, to enhance wanted ones, or both.
3. What are low-pass and band-pass filter and what is the difference between these two?
Ans: Low-pass filter allows frequencies below cutoff frequency.
High-pass filter allows frequencies above cutoff frequency
4. Why is the impulse response "finite.
Ans: Impulse response is finite, Because Impulse has only one sample.
5.What is the importance of decimation for a given signal/sequence?
Ans: Decimation for a given signal/sequence will reduce the sampling frequency to required level.
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UpdatedFeb 02, 2020
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Views2,578
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