Program to generate permutation
Program:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
int n, i, k = 0;
char a[10];
void perm(char a[10], int k, int n);
clrscr();
printf("Enter the string : ");
scanf("%s", a);
printf("\nThe permutation is :\n");
n = strlen(a);
perm(a, k, n);
getch();
}
void perm(char a[10], int k, int n)
{
char t, d[10];
int i;
if(k == n)
{
printf("\n%s", a);
return;
}
else
{
for(i = k ; i < n ; i++)
{
t = a[i];
a[i] = a[k];
a[k] = t;
strcpy(d, a);
perm(d, k + 1, n);
}
}
}
Output:
Enter the string : abc
The permutation is :
abc
acb
bac
bca
cab
cba
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UpdatedDec 30, 2019
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Views12,941
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