Program to find NCR value of the given numbers
Program:
#include<stdio.h>
#include<conio.h>
long fact(int);
void main()
{
long i, ncr;
int n, r;
clrscr();
printf("Enter the value for N : ");
scanf("%d", &n);
printf("\nEnter the value for R : ");
scanf("%d", &r);
if(n >= r)
{
ncr = fact(n) / (fact(n-r) * fact(r));
printf("\nThe NCR value is : %ld", ncr);
}
else
printf("\nCalculating NCR value is not possible");
getch();
}
long fact(int i)
{
long x;
if(i == 0)
return 1;
else
{
x = i * fact(i - 1);
return x;
}
}
Output:
Case: 1
Enter the value for N : 7
Enter the value for R : 5
The NCR value is : 21
Case: 2
Enter the value for N : 5
Enter the value for R : 7
Calculating NCR value is not possible
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UpdatedDec 30, 2019
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Views7,517
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