Program to find LCM
and GCD
of the given two numbers
Program:
#include<stdio.h>
#include<conio.h>
void main()
{
int n1, n2, prod, gcd, lcm;
clrscr();
printf("Enter the two numbers : ");
scanf("%d %d", &n1, &n2);
prod = n1 * n2;
while(n1 != n2)
{
if(n1 > n2)
n1 = n1  n2;
if(n2 > n1)
n2 = n2  n1;
}
gcd = n1;
lcm = prod / gcd;
printf("\nThe GCD is : %d", gcd);
printf("\n\nThe LCM is : %d", lcm);
getch();
}
Output:
Enter the two numbers : 10 8
The GCD is : 2
The LCM is : 40

CreatedOct 15, 2014

UpdatedDec 30, 2019

Views8,265
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