Performing arithmetic operations using switch...case
Program:
#include<stdio.h>
#include<conio.h>
void main()
{
int n1, n2, ch;
clrscr();
printf("Enter the first number : ");
scanf("%d", &n1) ;
printf("\nEnter the second number : ");
scanf("%d", &n2);
printf("\n[1] -> Addition ");
printf("\n[2] -> Subtraction ");
printf("\n[3] -> Multiplication ");
printf("\n[4] -> Division ");
printf("\n\nEnter your choice <1...4> : ");
scanf("%d", &ch);
switch(ch)
{
case 1:
printf("\n%d + %d = %d", n1, n2, n1 + n2);
break;
case 2:
printf("\n%d - %d = %d", n1, n2, n1 - n2);
break;
case 3:
printf("\n%d * %d = %d", n1, n2, n1 * n2);
break;
case 4:
printf("\n%d / %d = %.2f", n1, n2, (float)n1 / n2);
break;
default:
printf("\nInvalid choice");
break;
}
getch();
}
Output:
Enter the first number : 10
Enter the second number : 5
[1] -> Addition
[2] -> Subtraction
[3] -> Multiplication
[4] -> Division
Enter your choice <1...4> : 3
10 * 5 = 50
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UpdatedDec 30, 2019
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Views16,092
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