Mathematical Methods Mid - II, March - 2015
1.The formula to find (n+1) th approximation of root of f(x) = 0 by Newton Raphson method is
Answer: C
2.If by bisection method first two approximation x0 and x1 are 1 and 2 then x2 is
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1.5
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1.75
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2.0
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1.25
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Answer: A
3.If f(0) =3, f(0.5) = 3.5, f(1) = 4, f(1.5) = 4.75, f(2) = 4.25, then b y simpson’s 1/3 rd rule
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6.52
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7.85
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8.04
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10.23
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Answer: C
4.If y' = x − y2 and y(0) =1 , then by Picards method y(1) (x) = is
Answer: B
5.If y' = y − xh = 0.1, y(0.1) = 2.205, k1 = 0.2105 then k2 in Runge kutta fourth order formula is
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0.216
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0.228
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0.315
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1.25
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Answer: A
6.If f (x) = 0, − < x ≤ 0 = x, 0 < x < then a0 (fourier series) =
Answer: C
7.If f(x) = | x | in (– ,) then b1 = (fourier series)
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1
-
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1/2
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0
-
Answer: D
8.If f(x) = x sin x in 0 < x < then a0 in half range expansion of cosine series is
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0
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1
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1/2
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2/
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Answer: C
9.The fourier cosine transform of f(x) is
Answer: C
10.The finite fourier cosine transform of x in (0, ) is
Answer: C
11.
x | 1 | 1.5 | 2 | 2.5 | 3 |
f(x) | 2 | 2.4 | 2.7 | 2.8 | 3 |
Answer: 5.20
12.If first two approximations of root of xex-3=0 are 1 and 1.5 then by Regula falsi method the third approximation is………………………
Answer: 1.035
13.By simpson’s 1/3 rd rule, divide [0 3] into 3 equal parts, then …………
Answer: 1.406
14.If y' = x + y and y (0) = 1, up to 2nd decimal y(0.1) by Taylor series method is ...................................................
Answer: 1.11
15.If , h = 0 .5, y(0) = 1 then by Euler’s methody(1) = ...........................
Answer: 2.5
16.If f(x) = 0 for 0 < x < 1 = 1 for 1 < x < 2 then a1 in half range expansion of cosine series is ____________
Answer:
17.If f(x)= x2 – 2 in – 2 < x < 2 then b2 (fourier series) = __________
Answer: 0
18.The finite fourier sine transform of f(x) =x in (0, 2) is .................................
Answer:
19.If the finite fourier cosine transform of f(x) is ...............................
Answer:
20.If the fourier cosine tranform of e−ax is then fourier sine transform of xe−ax = ..................................................................
Answer: